QUESTION 13
A company has decided to use 0-1 (binary) integer programming to help to make some investment decisions. There are three possible investment alternatives from which to choose, but if it is decided that a particular alternative is to be selected, the entire cost of that alternative will be incurred (i.e., it is impossible to build one-half of a factory). The integer programming model is as follows:
Max 5000X1+7000X2+9000X3
S.t.
X1+X2+X3<=2 (only 2 may be chosen)
25000X1+32000X2+29000X3<=62000 (budget limit)
16X1+14X2+19X3<=36 (resource limitation)
All variables =0,1
where
X1=1 if alternative 1 is selected, 0 otherwise
X2=1 if alternative 2 is selected, 0 otherwise
X3=1 if alternative 3 is selected, 0 otherwise
The optimal solution is X1=0, X2=1, X3=1
According to information above, if the optimal solution is used, how much of the budget would be spent?
QUESTION 14
Refer to the previous investment decision problem 13. According to information above, what would be the optimal value of the objective function?
Answer
13)
The optimal Solution is X1 = 0, X2 = 1, X3 = 1
The Left-hand side of constraint for Budget is 25000*X1 + 32000*X2 + 29000*X3
Substituting the optimal solution in the above equation,
25000 * 0 + 32000 * 1 + 29000 * 1 = 61000
Answer: 61000
14)
The objective function = 5000*X1 + 7000*X2 + 9000*X3
The value of optimal objective function is obtained by substituting the optimal solution in above equation
5000 * 0 + 7000 * 1 + 9000 * 1 = 16000
Answer: 16000
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QUESTION 13 A company has decided to use 0-1 (binary) integer programming to help to make...
QUESTION 13 A company has decided to use 0-1 (binary) integer programming to help to make some investment decisions. There are three possible investment alternatives from which to choose, but if it is decided that a particular alternative is to be selected, the entire cost of that alternative will be incurred (i.e., it is impossible to build one-half of a factory). The integer programming model is as follows: Max 5000X1+7000X2+9000X3 S.t. X1+X2+X3<=2 (only 2 may be chosen) 25000X1+32000X2+29000X3<=62000 (budget limit)...
A company has decided to use 0-1 (binary) integer programming to help to make some investment decisions. There are three possible investment alternatives from which to choose, but if it is decided that a particular alternative is to be selected, the entire cost of that alternative will be incurred (i.e., it is impossible to build one-half of a factory). The integer programming model is as follows: Max 5000X1 +7000X2+9000X3 S.t. X1+X2+X3<=2 (only 2 may be chosen) 25000X1+32000X2+29000X3<=62000 (budget limit) 16X1+14X2+19X3<=36...
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