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Score: 0 of 1 pt 4 of 4 (4 complete) HW SI X 7.5.19-LS Use a graphing calculator or a computer program for the simplex method
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Answer #1
Iteration-1 Cj 90 70 60 50 0 0 0
B CB XB x1 x2 x3 x4 S1 S2 S3 MinRatio
XBx1
S1 0 490 0 0 0.375 0.625 1 0 0 ---
S2 0 570 0 0.75 0.5 0.375 0 1 0 ---
S3 0 300 -1 0.25 0.125 0 0 0 1 300/1=300→
Z=0 Zj 0 0 0 0 0 0 0
Zj-Cj -90↑ -70 -60 -50 0 0 0

Negative minimum Zj-Cj is -90 and its column index is 1. So, the entering variable is x1.

Minimum ratio is 300 and its row index is 3. So, the leaving basis variable is S3.

∴ The pivot element is 1.

Entering =x1, Departing =S3, Key Element =1

Iteration-2 Cj 90 70 60 50 0 0 0
B CB XB x1 x2 x3 x4 S1 S2 S3 MinRatio
XBx4
S1 0 490 0 0 0.375 -0.625 1 0 0 490/0.625=784→
S2 0 570 0 0.75 0.5 0.375 0 1 0 570/0.375=1520
x1 90 300 1 0.25 0.125 0 0 0 1 ---
Z=27000 Zj 90 22.5 11.25 0 0 0 90
Zj-Cj 0 -47.5 -48.75 -50↑ 0 0 90

Negative minimum Zj-Cj is -50 and its column index is 4. So, the entering variable is x4.

Minimum ratio is 784 and its row index is 1. So, the leaving basis variable is S1.

∴ The pivot element is 0.625.

Entering =x4, Departing =S1, Key Element =0.625

Iteration-3 Cj 90 70 60 50 0 0 0
B CB XB x1 x2 x3 x4 S1 S2 S3 MinRatio
XBx2
x4 50 784 0 0 0.6 1 1.6 0 0 ---
S2 0 276 0 -0.75 0.275 0 -0.6 1 0 276/0.75=368→
x1 90 300 1 0.25 0.125 0 0 0 1 300/0.25=1200
Z=66200 Zj 90 22.5 41.25 50 80 0 90
Zj-Cj 0 -47.5↑ -18.75 0 80 0 90

Negative minimum Zj-Cj is -47.5 and its column index is 2. So, the entering variable is x2.

Minimum ratio is 368 and its row index is 2. So, the leaving basis variable is S2.

∴ The pivot element is 0.75.

Entering =x2, Departing =S2, Key Element =0.75

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Iteration-4 Cj 90 70 60 50 0 0 0
B CB XB x1 x2 x3 x4 S1 S2 S3 MinRatio