Three capacitors, with capacitances C1 = 4.5 uF, C2 = 2.9 uF, and C3 = 2.1...

Question

Question

Three capacitors, with capacitances C1 = 4.5 uF, C2 = 2.9 uF, and C3 = 2.1 uF, are connected to a 20 -V voltage source, as sh

Answer 1

Answer #1

Finding Equivalent Capacitance :

C2 & C3 are in Parallel : $C ' = C2 + C3 = 2.9 + 2.1 = 5 \mu F$

C' & C1 are in Series : $C_{eq} = \frac{C ' C_1}{C' + C_1} = \frac{5*4.5}{5 + 4.5} = 2.37 \mu F$

Charge from the supply, $Q = C_{eq}V = 2.37 * 20 = 47.4 \mu C$

Voltage drop Parallel branches : $V' = V - \frac{Q}{C_1} = 20 - \frac{47.4}{4.5} = 9.47 V$

Charge across C2 : $Q_2 = C_2 V' = 2.9 * 9.47 = 27.46 \mu C \rightarrow Answer$

Answer 2

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