Question

Obtain the required confidence interval. You may assume normal distributions. A researcher was interested in comparing the amount of time spent watching television by women and by men. Independent simple random samples of 14 women and 17 men were selected, and each person was asked how many hours he or she had watched television during the previous week. The summary statistics are as follows. Men Women x1 - 1242 - 143 52-52 ni - 14 n2 = 17 91-39 Determine a 99% confidence interval for the difference, u1 - 42 between the mean television watching times for women and men. OA) -6.41 to 2.61 hours B) -6.42 to 2.62 hours OC) -6.54 to 2.74 hours OD) -6.55 to 2.75 hours

Answer 1

(3.9)2 14 + (5.2² = 1.64. 1) SE- 12 ni ne Dan+= 2 = 24. for 99% of confidence, ta/2in1 = 2-156. The margin of the error = t ta(SE) E = 4.52. The 99% of confidence Interval is ak-ał-E < Mila <3 ty +E -1.9-452 <Mila <-19+4.52 -6.42 <li-M2 < 2.62 cię option 6