Question

Question 2 The figure shows the free-body diagram of a connecting-link portion having stress concentration at three sections. The dimensions are r=0.25 in. d=0.40 in, h = 0.50 in, wl= 3.50 in, and w2 = 3.0 in. The forces F fluctuate between a tension of 15 kip and a compression of 46 kip. Neglect column action and find the least factor of safety if the material is cold-drawn AISI 1018 steel T- Section A-A I

Answer 1

Here , they were not mentioned solve the problem using any particular method, so I choose the goodman equation to find the least factor of safety. And The FoS is 0.121

Given data: 75 0.25 in V shi وفا حرا d = 0.4 in. h = 0.5 in. W,- 3.5 in. W₂=3 in. 94 ad W A F = 15 tension fi 46 kip compressien. us Man stress : u= 64 kpsi Cold-drawn AISI 1018 ry: sukpsij steel Table A-Lo Determinstie ASTM 15 man 드 man F (Lord) xh (3.5-0.40.5 kipl Ғ, хи 4684 TY TT (0.2812 = 9.6 77 - Min stress : inz mina v 937.104 kipline q Alternating stress 937.104-9.677 as min-amane 2 2 - 46.714 kiplina s mean stress 937.104 +9.677 O ma maut min L cue can =473.391 killine Goodman fernula to find ag laast FOS. m 1 ru om ta Fos - ory fos ogom trago 64 x 64 FOS 0.121 (su x473.391)+(46.714X64) Fos 0.121