Given data,
z = 1.40
a)
Claim : p ≠ 0.234
This is two tailed test.
The null and alternative hypothesis is
H0 : p = 0.234
Ha : p ≠ 0.234
b)
p-value = 2 * P(Z > z)
= 2 * P(Z > 1.40)
= 2 * 0.0808
= 0.1616
c)
Since p-value > 0.05 significance level,
Fail to reject H0
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