Question

According to the financial reports by Snapchat, the average daily user of Snapchat created 19 messages, or "snaps," per day creates a random sample using information from students on her campus for the current semester, with the accompanying re Click the icon to view the daily snaps data. a. Using a = 0.05, test the hypothesis that the number of Snapchats sent by the average Snapchat user has not changed sin Determine the null and alternative hypotheses. HOH H:H (Type integers or decimals. Do not round.) Determine the appropriate critical value. Select the correct choice below and fill in the answer box within your choice. (Round to three decimal places as needed.) OA -= OB 1/2" OC. Calculate the appropriate test statistic, (Round to two decimal places as needed.) State the conclusion. Ho. There sufficient evidence to conclude that the number of Snapchats sent by the average Snap b. Determine the precise p-value for this test using Excel. The p-value is Click to select your answer(s).

Answer 1

Answer Date: 30/07/2020 To test the hypothesis is that the number of Snapchats spent by the average Snapchat users has not changed since Q3 2017 at 5% significance level. a) The null and alternative hypothesis is, H:H=19 H:4 19 The t-critical value is, The sample size is small and two-tailed test. Look in the column headed a = 0.05 and the row headed in the t distribution table by using degree of freedom is, d.f.=n-1 = 20-1 = 19 The t-critical value is 2.093.

The correct answer is B The t-test statistics is, First, compute mean and standard deviation then find the t-test statistics. The sample mean is, = n 21+9+16 +28+ ..... +14+21+28 +18 20 = 20.75

The sample standard deviation is, S= (x - ) n-1 (21- 20.75)2 + (9- 20.75)2 + ..... +(28 – 20.75)2 +(18-20.75) 20-1 = 8.258 = The t-test statistics is, K- (s/n) 20.75-19 8.258/20 = 0.9477 = 0.95 The t-test statistics is 0.95 Conclusion

The t-test statistics which is 0.95 is less than t-critical value which is 2.093, so do not reject the null hypothesis at 5% level of significance. There is not sufficient evidence to indicate that the number of Snapchats spent by the average Snapchat users has changed since Q3 2017. The result is not statistically significant. b) The p-value is, By using Excel software, find p-value with the help of the following steps: 1) Select TDIST from Functions. 2) Enter X, Deg_freedom and Tails. 3) Click Ok. = 0.9477 TDIST X 0.9477 Deg_freedom 19 Tails 2 = 19 = 2 = 0.355180913

From Excel output, the p-value is 0.3552