Question

need the test-statistic and the p-value!

A researcher is interested in investigating whether living situation and pet ownership are dependent. The table below shows the results of a survey. Frequencies of Living Situation and Pet Single Family Couple Dog 57 88 85 Cat 93 74 46 Various 44 53 52 None 54 56 49 What can be concluded at the a= 0.01 significance level?

Answer 1

Null hypothesis: there is no association between the two variables i.e. living situation and pets.

Alternative hypothesis: there is an association between the two variables i.e. living situation and pets.

Results Row Totals Dog 230 Cat Single 57 (73.98) [3.90] 93 (68.51) [8.75] 44 (54.36) (1.97] 54 (51.14) [0.16] Family 88 (86.81) [0.02] 74 (80.39) (0.51] 73 (63.79) (1.33] 56 (60.01) [0.27] Couple 85 (69.21) [3.60] 46 (64.09) [5.11] 52 (50.85) [0.03] 49 (47.84) [0.03] 213 None 169 Others 159 Column Totals 248 291 232 771 (Grand Total) The chi-square statistic is 25.6718. The p-value is .000256. The result is significant at p<.01.

X$ 10-E)? 0 = observed values E = Expected Values E [ Single, Day) - 230 x 248 E E 73,98 กา) have Expected 2 Similarly in l l above table, we values, X (single, Dog) = 157-73.93) Similarly for square each cell. in 3.90 73,98 others, [ ]. chi- statistic for 2 X 25.6718 0.01 ولس 7 the reject & p-value 0.000256 < null hypetheris association between d-0.01. There is living situation and pets.