When making some vinegar based pickles, some 4.95 % by volume vinegar was diluted according to a recipe. What is the concentration in molarity (M, mol/L) of the vinegar if you added 2.325 L water to 0.400 L of the 4.95 % vinegar? Potentially useful information: density of the vinegar is 0.960 g/mL and the molar mass of vinegar is 60.052 g/mol.
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When making some vinegar based pickles, some 4.95 % by volume vinegar was diluted according to...
Vinegar is sold as % acidity which means a weight/volume or w/v% calculation. The density of acetic acid is 1.05 g/ml and water is (effectively) 1.0 g/ml. Recollect (from CHMY121) the %w/v refers to a solution with a certain mass of additive made up to 100 mL with the addition of (in this case) water; or % m/v= (grams of solute / 100 mL solution) ×100 The molar mass of Acetic Acid is 60.052 g/mol. What is the molarity of...
(4) If a 1.0L sample of 5% vinegar was diluted with distilled water so that the final volume was 2.4 L what would be the new concentration in mols dm'? (5) What concentration NaOH should be used for your lab if that is what I did with the original vinegar? (choose the best option) (A) 0.0100 M (C) 0.25 (B) 0.100 M (D) 1.00 M (E) 2.00 M (6) Potassium Hydrogen Phthalate (KHP) is used as a primary standard (to...
6.31 M 7. Molarity of acetic acid, HC2H30in vinegar sample (show your calculations) Volume of vinegar sample = 0.003L 0.003L Vinegar contain 0.01893 moles IL 0.01893 = 6.3 IM 0.003 Vinegar contain 8. Grams of Acetic Acid, HC,H,O2 (show your calculations) 1.1368 g HC2H5O2 Grams acid = 12 *MW = 0.01893 mot x 60.052 g/ mot = 1-1368 g 31.90 % L 3 100 9. Percent (m/v) of HC,H,O, in vinegar sample (show your calculations) 3.0 mL vinegar contain 0.01893...
fill in 5-9 A. Preparation of Vinegar Sample Brand of vinegar Trial 1 Trial 2 1. Volume of vinegar used (mL) 2. Density of vinegar (g/mL) 3. Mass of vinegar used (g) solution - P.V. 5.0 1002 5.01 5.0 1.000 5.01 B. Analysis of Vinegar Sample 1. Buret reading of NaOH, initial (mL) 2. Buret reading of NaOH, final (mL) 3. Volume of NaOH used (mL) 0 0 43.60 46,90 42.60 41.90 1005 4. Molar concentration of NaOH (mol/L) 5....
I need it right now, please help me?? PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The vinegar solution must be diluted by a factor of 5 to be suitable for titration. 1. Obtain - 20 ml of the stock vinegar solution from the fume hood. 2. Using the 10-ml. pipet, pipet" 10 mL of the stock solution to a 50-ml volumetric flask. 3. Fill the volumetric flask to the calibration line with distilled water. Be sure not to go over...
4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml...
Please help with calculations and solutions written out. Thank you! Calculate the approximate volume of the vinegar sample needed for the analyses Mass of flask (g) Mass of flask + vinegar (g) Mass of vinegar (g) Buret reading of NaOH_2 initial (mL) Buret reading of NaOH, final (mL) Volume of NaOH used (mL) Molar concentration of NaOH (mol/L) Moles of NaOH added (mol) Moles of CH-3COOH in vinegar (mol) Percent by mass of CH_3COOH in vinegar(%) Average percent by mass...
a-c 5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor) 25.0 mL of vinegar are diluted to 100.0 mL and 10.0 mL samples of this solution are titrated against 0.100 mol L-NaOH solution. An average of 18.1 mL NaOH are required to neutralize the vinegar. You will need to calculate the concentration of the diluted solution and hence the percentage concentration of acetic acid in the original vinegar via the following questions: CH COOH(aq)...
can someone help me with these lab questioins on titration of diluted vinegar When titrating an acid with a base, phenolphthalein is often used to indicate the end of the titration. When placed in an acidic solution, phenolphthalein turns the solution a. b. green colourless pink. a milky white. C. d. To make a standard NaOH solution, about 13 mL of 3 M NaOH is mixed with about 300 mL of deionized water (H2OD) in a 500 ml beaker. Why...
I MAINLY NEED HELP ON TABLES PLS HELP THANK YOU Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC2H4O4, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 mL water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the...