Question

Below is a matrix of random numbers. Find the mean, median, and mode of the matrix. B=[0 1 2 3 4 50 689 23092 68 40 7] Sort Matrix Z so that the largest numbers of each row are in the first column and smallest numbers descend towards the last column. Must use sort function.

How do I solve using Matlab?

Answer 1

B=[0 1 2 3 4;5 0 6 8 9;2 3 0 9 2;6 8 4 0 7];
mean_B=mean(mean(B));
median_B=median(median(B));
B=[flip(sort(B(1,:)));flip(sort(B(2,:)));flip(sort(B(3,:)));flip(sort(B(1,:)))];
fprintf("Mean of matrix B is: %f\n",mean_B);
fprintf("Meadian of matrix B is: %f\n",median_B);
disp("Sorted matrix is:\n");
disp(B);

C:\Octave\OCTAVE-1.0\mingw64\bin\octave-gui.exe octave:43> B=[0 1 2 3 4;5 0 6 8 9;2 3 0 9 2;6 8 4 0 7]; octave:44> mean_B=mean(mean(B)); octave:45> median_B=median(median(B)); octave:46> B=[flip(sort(B(1,:))); flip(sort(B(2,:)));flip(sort(B(3,:)));flip(sort(B(1,:)))]; octave:47> fprintf("Mean of matrix B is: %f\n", mean_B); Mean of matrix B is: 3.950000 octave:48> fprintf("Meadian of matrix B is: %f\n", median_B); Meadian of matrix B is: 3.500000 octave:49> disp("Sorted matrix is: \n"); Sorted matrix is: octave:50> disp(B); 4. 3 2 1 0 9 8 6 5 0 9 3 2 2 0 4. 3 2 1 0 octave:51> o 1 1 Type here to search D C ENG 08:55 30-07-2020