Question

A food safety guideline is that the mercury in fish should be below 1 part per million (ppm). Listed below are the amounts of mercury (ppm) found in tuna sushi sampled at different stores in a major city. Construct a 95% confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is too much mercury in tuna sushi? 0.53 0.71 0.11 0.98 1.36 0.50 0.84 What is the confidence interval estimate of the population mean? ppm<u<ppm (Round to three decimal places as needed.)

Answer 1

Sol> triven data. 0.53, 0.71, Ooll ,0.98 ,1.36 ,0.50 ,0.84 Sample meam (X) = sum of term number of ferm 0.53+0.71+ 0.11 +0.98+ 1.36+0.50+0.84 7 5.03 7 y = 0.7186 Sample standard deviation (S), S = I N N-1 i=1 3 (%;-Xj2 (0.53-0-7186)+(0.71-0.718674 + --+(0.50-0.7186) +0.84-0.7186) 7-1 0.948285721 6 Jo. 15804762 5 F0.3976

Al, 95% confidence interwal estimate of the population mean (M) a= (1-0.95) = 0.05 Degree of freedom (df) = n-1 - 7-1 - 6 Critical value =(x=0.05 ,df=6) Critical value = 2.4469 95. CI, CI = Y + taia Jn 0.3976 = 0.71867 2.4469 * = 0.7186 ± 0.3677 - (0.7186-0.3677), (0.7186 +0.3677) 0.3509 ppm < u < 1.08631ppm 95% CI since, I is between 0.3509 and 160863, it appears that the mean mearcury in fish is not below I part per million and thur, There could be too much mercury in tuna sushi