linear algebra Find the matrix A' for T relative to the basis B'. T: R2 R2,...
Find the matrix A' for T relative to the basis B'. T: R2 R2, 7(x,y) - (-9x + y, 9x - y), 8' = {(1, -1), (-1,5)} A' 11
Find the matrix A' for T relative to the basis B'. T: R2 + R2, T(x, y) = (3x - y, 4x), B' = {(-2, 1), (-1, 1)} A' = Let B = {(1, 3), (-2,-2)} and B' = {(-12, 0), (-4,4)} be bases for R2, and let 0 2 A = 3 4 be the matrix for T: R2 + R2 relative to B. (a) Find the transition matrix P from B' to B. 6 4 P= 9 4...
Find the matrix A' for T relative to the basis B'. T: R2 → R2, T(x, y) = (5x – y, y - x), B' = {(1, -2), (0, 3)} A' =
linear algebra Find the coordinate matrix of x in RP relative to the basis B'. B' = {(1, -1, 2, 1), (1, 1, -4,3), (1, 2, 0,3), (1, 2, -2, 0)}, x = (16, 10,-8, 7) [x]B 11
12: Find a basis B for R', such that the matrix for the linear transformation T: R' R', T(x,y,z)-(2x-2z,2y-2z,3x-3z) relative to B is diagonal. 12: Find a basis B for R', such that the matrix for the linear transformation T: R' R', T(x,y,z)-(2x-2z,2y-2z,3x-3z) relative to B is diagonal.
Find a basis B for the domain of T such that the matrix for T relative to B is diagonal. T: R3 → R3: T(x, y, z) = (-3x + 2y – 32, 2x - 62, -* - 2y – z) -4 0 0 0 -4 B = 0 0 X Need Help? Read It Watch It Talk to a Tutor
linear algebra Find the matrix representation of T relative to the bases B and C a + b + c T: P2+, Ta + bx + cx?) = a+b-C a-b+c B = {1, x,x?}, Ca c-000 1-45 -2 1-3 3 0 2 B.C b. MBC 5 1 1 -3 2-2 1 -1 3 c. MC 1-1 2 0 2 -2 0 0 1 d. мас 1 1 - 1 1 - 1 e. B,C 0 0 2 02-2 1-1 1...
Find the matrix A' for T relative to the basis B'. T: R3 → R3, T(x, y, z) = (x, y, z), B' = {(1, 0, 1), (0, 1, 1), (1, 1, 0)} A' = 11 JITE
linear algebra Let T: R2 R2 be a reflection in the line y = -x. Find the image of each vector. (a) (-3,9) (b) (5, -1) (c) (a,0) (d) (o, b) (e) ( ed) (f) (9)
Find a basis B for the domain of T such that the matrix of T(x, y) = (3x + 3y, 3x + 3y) relative to B is diagonal. a B = {(1, -1), (1, 1)} b B = {(1,0), (0, 1); c. B = {(1, 0), (1, 1); d. B = {(1, -1), (1, 0)) e B = {(0, 1), (1, 1);