We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
The reagents that were in the choices were BaCl2 and CaCl2 and I chose BaCl2. The...
reagent is BaCl2 Determining the amount of sulfate ion (SO2) dissolved in seawater in the unit of molarity QUESTION Using the reagent you pick in the previous Question #3, write up a very detailed laboratory experiment procedure that will allow you to determine the molar concentration of sulfate ion dissolved in the seawater. A clear, overall steps are already introduced with the pictures and the sketch in Question #2 along with the calculation procedure in Question #1. Imagine yourself not...
ANSWER ONLY QUESTION 4, QUESTION 3 is for reference only QUESTION 3 Determining the amount of sulfate ion (SO.2-) dissolved in seawater in the unit of molarity As we all know seawater is salty. This is because many salt ions are dissolved in the seawater, which is not the case in the freshwater. Among many ions, Nat and Clare the most abundant ions dissolved in the seawater followed by SO,, Mg²+, Ca?', and Kions. So sulfate (S0?) ion is the...
An unknown metal sulfate is found to be 55.66% SO42 by mass. Assuming that the charge on the metal cation is +3, determine the identity of the cation 1. 2. The unknown metal sulfates are hygroscopic and will absorb water from air. They must thus be kept in desiccators to remove any absorbed water and keep them dry. How would your results be affected if your unknown sample was not desiccated? Would you obtain a hig her or lower mass...
What is the theoretical yield of H2SO4 + BaCl2 ---> BaSO4 + 2HCl Given data: Concentration of BaCl2 = 0.20 M Concentration of H2SO4 = 6 M volume of H2S04 = 5.00 mL What is the theoretical expected yield of precipitate as calculated using stoichiometry? Compare actual yield and theoretical yield. Calculate percent yield. Data: Trial 1: Mass of BaSO4 precipitate = 0.191 g Trial 2: Mass of BaSO4 precipitate = 0.187 g What is the Millimoles of BaSO4 for...
Determining the amount of sulfate ion (SO2) dissolved in seawater in the unit of molarity QUESTION Sulfate concentration in the seawater is about 28 mm (0.028 M). Take the reverse approach to the calculation procedure in the previous Question #1 (so called a backward calculation) and find a rough estimate for the volume of the seawater sample you may need to take from the beach like the one below. A 20.0 mL sample solution contains unknown amount of bromide ion...
how do you do this ? Some Calculations You started out with a known amount of harium chloride and sodium sulfate. How much solid product should you collect? Show your calculations. How much did you collect? What is your percent yield? Which reactant should be the limiting reagent? Which reactant should be the excess reagent? Proving the identity of the Limiting and Excess Reagents There are two scenarios for the identity of the contents of the beaker containing the filtrate....
I need help figuring these calculations out Mental Data Reagents ass of weighing Boat/Paper Trial Trial 2 Mass of Weighing Weighing Boat/Paper and Ba(NO3)2 31 Mass of Ba(NO3)2 Mass of weighing Boat/Paper 55 of Weighing Boat/Paper and NH,SO. HT 2.493 Mass of NH SO,H Precipitate Trial 1 Trial 2 Mass of Filter Paper 0.446 Mass of Filter Paper and Precipitate Mass of Precipitate Mass Ratio Average Mass Ratio? "Precipiate must be room temperature before the moss is determined. Use the...
EXPERIMENTAL PROCEDURE 1. Using a 50.0 mL graduated cylinder, obtain 40.0 mL of the unknown water sample. This ample contains an unknown amount of BaCh, Pour this into a 100 mL beaker 2. Add 20.0 ml. of the NasPO solution provided to your unknown solution in the 100 ml, beaker The amount of NaPOs you are adding in the 20.0 ml, of solution is more than enough to provide for complete reaction of the unknown BaClh, Consequently, you can be...
Question A 20.0 mL sample solution contains unknown amount of bromide ion (Br). To this solution was added the solution that contains plenty of AgNO3. AgBr precipitates were formed. The precipitate were filtered and measured to be is 0.6964 g. What is the molarity of bromide ion in the original sample solution? The molar mass of Br = 80.0 g; the molar mass of AgBr = 188 g. (Solution) AgNO, is soluble and thus exists Ag+ ion and NO3-ion. Ag+...
I think I calculated the precipitate correctly. I got 1.151g. I did this by adding the g of cobalt synthesize product to the g of AgNO3. I just cant figure out how to solve for B PART F (GRAVIMETRIC ANALYSIS) 53.589 Gravimetric analysis is a technique used to quantitatively determine the amount of an analyte based on its mass. In this particular case, a solution of silver nitrate will be added to a solution of the synthesized compound and the...