Question

please help with this question

A stunt pilot weighing 0.70 kN performs a vertical circular dive of radius 0.80 km. At the bottom of the dive, the pilot has a speed of 0.20 km/s which at that instant is not changing. What force does the plane exert on the pilot? 4.3 kN up 5.6 kN up 2.3 kN up 5.6 kN down 4.3 kN down

Answer 1

Option A is the correct answer.

Solution's 8oom 200 m/sec Radius (O) = 0.80 km. Va 0:20 kms W = 0.70 KN 700 N 7005 70 kg R- Reaction foxe R = fot mg m- so AR oll R= mv² + mg & Fo ng 2 ca R = 70x1200) 800 + 700 Ige lomlsee? ] R = 1 4200 N R = 4.2 KN ] up vi if we take g= 9.81 m/sec? then R= 4.3KN up by Hence force exert "plane On pilot.