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For the table show, determine the Direct Runoff depth. Express in the nearest whole number value in mm. Note that the given i

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Answer #1

Base flow = 11.34 m3/s

Watershed area = 18.22 km2

Direct run-off = Observed run-off - Base flow

Time Observed rainfall Observed Runoff Base flow Direct runoff
hours mm m3/s m3/s m3/s
09:00 43 23 11.34 11.66
09:30 53 65 11.34 53.66
10:00 5 161 11.34 149.66
10:30 5 270 11.34 258.66
11:00 312 11.34 300.66
11:30 233 11.34 221.66
12:00 122 11.34 110.66
12:30 63 11.34 51.66
13:00 51 11.34 39.66
13:30 35 11.34 23.66
14:00 20 11.34 8.66
Sum= 1230.26 m3/s

Direct run-off depth = Total volume of direct run-off/Area of basin

=\frac{(\Sigma O)*t*60*60}{A*10^{6}} = 0.36*\frac{{(\Sigma O)*t}}{A} cm

where t = Time interval between successive ordinates in hours

A = Area of basin in km2

\SigmaO = Sum of discharge ordinates (direct run-off) in m3/s

Direct run-off depth = 0.36*\frac{1230.26*0.5}{18.22}= 12.154 cm = \mathbf{\mathit\underline{{12 cm}}}

Direct run-off depth = 120 mm

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