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ОА A wire 15.0 m long has a diameter of 0.321 mm. When 1.50 V is applied across the ends of the wire, the current is 0.0833 A
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Length of the wire = b = 15m. إلى - m Solution) -3 Diameter = 0.321 mm = 0.321x10 (wirlent in the wire =1= 0.0833 A across thg to Law v=IR & R = R=v accordir Ohms :. R = 18 12 * Ialso, R= pl A § f resistivity of the Materiat A Area of cross- section => 18xA=8 I → long th of the wire I - 18x r d² 4 h 18

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