Question

The relative fitness of three genotypes at a particular locus are W₁₁=0.65, W₁₂=0.75, W₂₂=0.9. Four populations have the following set of allele frequencies. In which population will the change in allele frequencies (due to selection) be the most rapid? (Show work) CLEAR hand writing or typing

A.    p = 0.86 & q = 0.14

B.    p = 1.0 & q = 0.0

C.   p = 0.05 & q = 0.95

D. p = 0.49 & q = 0.51

Answer 1

Fourth population has the largest change in allelic frequency so in this population, the change is rapid.

0.86 P = 0.9 population WIL = 0.65 + w mean = 0.14 Wiz - 0.75 Wz2 fitness p² Will + 2pq Wiz t q²W 22 0.480747 0.1806 + 0.01764 = 0.679 News frcq e-p' per tal p²W/1 + b quiz 0.48074 +0.09= 0.84 0.679 q'- qW22+ $ą, W12 = 0.01764+0.09 = 0.16 0.86-0.84 Change - W 0-679 W 0.02 population P = 1 0.65 7 Wi 13 W 12 = 0.75 Wzz = 0.9 p wit 2pawis & q² W22 menn fitness o to 0.65 t 0.65

APCO Date: Page New frequency op'- p²W, 1 + pq w,2 - 0.65 = 1 =q²W 22 + p q W12 w q 0.65 W Change 1-1=0 3rd 3 population p = 0.05 0.95 q Wil = 0.65 W 12 = 0.75, W22 = 0.9 fitness 0.0016 + 0.071 t 0-812 0-884 mean New frequency ap's w q p²wil + p q W 12 0.0016 + 0.035 0.04 00884 q²W 22 + p q W 12 = 0.8127 0.035 = 0.958 Or884 0096 0.05-0.04 - 10.01 w Or change 4th p 0.49 q = 0.51 W2 2 = 0.9 pohuation W1 = 0.65, W122 0.75 fitness mean W = 0.15 606+ 0.3748 t 0-23409 0.7649 - 0.156067 0.1874 0-45 0.7649 New freq = p = p²W + pq W12 q = q Was + pq W12 - 0.23 409 +0.1874 = 0+55 Change 0.04 w 0-7649 0.49 -0.45 =