Question

86.bg PART TWO: DATA AND RESULTS Metal: Aluminum (Cal = 0.217 cal/qE)-specific granity Data Item Trial 1 Trial 2 1. Mass of metal 50.og 2. Mass of calorimeter 3. Mass of calorimeter and water 124.49 4. Mass of water 120g 5. Initial temperature of water 24°C 23°C 6. Initial temperature of the metal 25°C 75°C 7. Final temperature of the mixture 21.11°C 152.6 g 8. Calculation of the heat energy gained by the water, Q Trial Onc: Trial Two: see the attachment for calculatos Qarine - mee(Tf-Tic). = 152-6-1-(2401) - 24) Gainel = 16.786 cal Need to calculate following Trial 9. What is the heat energy lost by the metal, Q? Remember, Q - Q Trial One: Trial Two: a lost = my. Ca. (Tf - Tie) Need to calculate following = 86-6.6-219 (241-25) E 18.7922 (-0-89) Trial I 10. 118 m 2 , then c- Q/m AT. Calculate c , the specific heat of the metal. 16.73 Cal Need to calculate following 86,6g (-00892) Trial I = 0.217 cal/ goc 11. The accepted value of the specific heat, c, for each metal sample: Trial One: Trial Two: Trial One: Trial Two: CAL = 0.217 Callge CAI= 0.217 Call callye Physical Science

Answer 1

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