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The step responses of a series RLC circuit are ve = 60 – 100-2000t – 10e-4000t V, t> 0 and i_ (0) = 3e-2000t + 6 e -4000t mA,

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Given RLC series circuit 4ovot ů = 3 e-zoot mA+70 t6e- R L Vs VC = 60-10-200+ aloe-4 over V, +70 lei=ic in cinuit Here this VHere I am uploading the solution if you have any doubt you can leave the comment.

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