Homework Answers
Given data :
mass of skier (m) = 60 kg
speed at pt. A (Va) = 5 m/s
yA = 15 m
equation of curve
y = (0.025x2 + 5)
at pt. B slope of curve is zero
thus on differentiating equation curve with respect to x and equate to zero
dy/dx = 0.025*2*x = 0
x = 0
thus slope is zero at x = 0
now value of y coordinate at x = 0
yB = 0.025*0 + 5
= 5 m
now applying conservation of energy principle at pt.A and B
Total Energy at A = Total Energy at B
m*g*yA + 1/2*m*Va2 = m*g*yB + 1/2*m*VB2
60*9.81*15 + 1/2*60*52 = 60*9.81*5 + 1/2*60*VB2
98.1 + 12.5 = 1/2*VB2
VB = 14.87 m/s
thus velocity of skier at pt. B is 14.87 m/s
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