Solution,
2) At 88% confidence level
= 1 - 88%
= 1 - 0.88 = 0.12
/2
= 0.06
Z/2
= Z0.06 = 1.55
part 2 Question 1 of 5 (1 point) View problem in a pop-up Find each of...
part 1
Question 1 of 5 (1 point) View problem in a pop-up Find each of the following. Enter your answers rounded to two decimals. Part 1 out of 5 22/2 for the 95% confidence interval za/2 CHECK
Question 1 of 5 (1 point) View problem in a pop-up Find each of the following. Enter your answers rounded to two decimals. Part 1 2. for the 95% confidence interval -1.96 Part 2 zaz for the 88% confidence interval 2.21.55 Part 3 out of 5 3a/2 for the 99% confidence interval 2a/2
Question 7 of 9 (1 point) View problem in a pop-up 7.1 Section Exercise 11 For a random sample of 70 overweight men, the mean of the number of pounds that they were overweight was 30. The standard deviation of the population is 4.4 pounds. Round intermediate answers to at least three decimal places. Round your final answers to one decimal place. Part 1 The best point estimate of the mean is 30.0 pounds. Part 2 out of 4 Find...
Question 7 of 9 (1 point) View problem in a pop-up 7.1 Section Exercise 11 For a random sample of 70 overweight men, the mean of the number of pounds that they were overweight was 30. The standard deviation of the population is 4.4 pounds. Round intermediate answers to at least three decimal places. Round your final answers to one decimal place. Part 1 out of 4 The best point estimate of the mean is pounds. CHECK NEXT 7.1 Section...
Question 4 of 5 (1 point) View problem in a pop-up Find the critical value ta/2 needed to construct a confidence interval of the given level with the given sample size. Round the answers to three decimal places. Part 1 For level 90% and sample size 7 Critical value-1.943 Part 2 For level 98% and sample size 11 Critical value =2.764 Part 3 out of 4 For level 95% and sample size 25 Criticeal value- CHECK NEXT
Question 7 of 9 (1 point) View problem in a pop-up 7.1 Section Exercise 11 For a random sample of 70 overweight men, the mean of the number of pounds that they were overweight was 30. The standard deviation of the population is 4.4 pounds. Round intermediate answers to at least three decimal places. Round your final answers to one decimal place. Part 1 The best point estimate of the mean is 30.0 pounds. Part 2 Find the 90% confidence...
Question 6 of 11 (3 points) View problem in a pop-up For the given confidence level and values of x and n, find the following. x = 48, n = 95, confidence level 80% Round the answers to four decimal places, if necessary. Part 1 out of 3 Find the point estimate. The point estimate for the given data is CHECK NEXT
Question 12 of 19 (1 point) View problem in a pop-up 10.2 Section Exercise 13 Question Traiic accidents: Traffic engineers compared rates of traffic accidents at intersections with raised medians with rates at intersections with two-way left-turn lanes. They found that out of 4655 accidents at intersections with raised medians, 2281 were rear-end accidents, and out of 4585 accidents at two-way left-turn lanes, 2037 were rear-end accidents. Check Answ Solve It Guided Solutio Part 1 out of 2 Assuming these...
Question 2 of 5 (1 point) View problem in a pop-UR 8.2 Section Exercise 17-20 (table A sample of size 52 has sample mean x = 53.4 and sample deviations -- 9.4. Part 1 Construct a 90% confidence interval for the population mean w. Round the answers to one decimal place. A 90% confidence interval for the population mean 4 is S.A. <<55.6 Part 2 out of 2 If the sample size were * = 48. would the confidence interval...
Question 3 of 6 (1 point) View problem in a pop-up 3.3 Section Exercise A student graduated from a 4-year college with an outstanding loan of $10,208, where the average debt is $8588 with a standard deviation of $1808. Another student graduated from a university with an outstanding loan of $12,072, where the average of the outstanding loans was $10,365 with a standard deviation of $2124. Part 1 out of 2 Find the corresponding z score for each student. Round...