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Question 7 of 9 (1 point) View problem in a pop-up 7.1 Section Exercise 11 For a random sample of 70 overweight men, the mean
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Hee we need to find 95% confidence interval of mean of these pounds.z score for 95% confidence interval is1.96 as P(-1.96<z<1.96)=0.95

Now we will findmargin of error,E=z*\frac{\sigma}{\sqrt{n}}=1.96*\frac{4.4}{\sqrt{70}}=1.031

95% Confidence interval for mean CI =\mu\pmE=30\pm1=(29,31)

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