Question 7 of 9 (1 point) View problem in a pop-up 7.1 Section Exercise 11 For...

Question

Question

Add a comment Improve this question Transcribed image text

Answer 1

Answer #1

Answer: given Sample mean = 30 population standard deviation (6)= 44 pounds n=70 Part 2) out of 4 90%.confidence intervail =

Add a comment

Answer 2

Similar Homework Help Questions

Question 7 of 9 (1 point) View problem in a pop-up 7.1 Section Exercise 11 For...

Question 7 of 9 (1 point) View problem in a pop-up 7.1 Section Exercise 11 For a random sample of 70 overweight men, the mean of the number of pounds that they were overweight was 30. The standard deviation of the population is 4.4 pounds. Round intermediate answers to at least three decimal places. Round your final answers to one decimal place. Part 1 out of 4 The best point estimate of the mean is pounds. CHECK NEXT 7.1 Section...
Question 7 of 9 (1 point) View problem in a pop-up 7.1 Section Exercise 11 For...

Question 7 of 9 (1 point) View problem in a pop-up 7.1 Section Exercise 11 For a random sample of 70 overweight men, the mean of the number of pounds that they were overweight was 30. The standard deviation of the population is 4.4 pounds. Round intermediate answers to at least three decimal places. Round your final answers to one decimal place. Part 1 The best point estimate of the mean is 30.0 pounds. Part 2 Find the 90% confidence...
Question 4 of 7 (1 point) View problem in a pop-up 7.2 Section Exercise 36 (table)...

Question 4 of 7 (1 point) View problem in a pop-up 7.2 Section Exercise 36 (table) Electricity bills: According to the U.S. Energy Information Administration, the mean monthly household electricity bill in the United States in 2011 was $110.42. Assume the amounts are normally distributed with standard deviation $22.00. Round the answers to four decimal places. Part 1 out of 3 What proportion of bills are greater than $128? The proportion of bills that are greater than $128 is CHECK...

part 1 Question 1 of 5 (1 point) View problem in a pop-up Find each of...

part 1 Question 1 of 5 (1 point) View problem in a pop-up Find each of the following. Enter your answers rounded to two decimals. Part 1 out of 5 22/2 for the 95% confidence interval za/2 CHECK
Question 2 of 5 (1 point) View problem in a pop-UR 8.2 Section Exercise 17-20 (table...

Question 2 of 5 (1 point) View problem in a pop-UR 8.2 Section Exercise 17-20 (table A sample of size 52 has sample mean x = 53.4 and sample deviations -- 9.4. Part 1 Construct a 90% confidence interval for the population mean w. Round the answers to one decimal place. A 90% confidence interval for the population mean 4 is S.A. <<55.6 Part 2 out of 2 If the sample size were * = 48. would the confidence interval...
Question 12 of 31 (1 point) View problem in a pop-up 9.4 Section Exercise 16 National...

Question 12 of 31 (1 point) View problem in a pop-up 9.4 Section Exercise 16 National statistics show that 23% of men smoke and 18.5% of women do. A random sample of 159 men indicated that 40 were smokers, and of 129 women surveyed, 17 indicated that they smoked. Part 1 out of 2 Construct a 90% confidence interval for the true difference in proportions of male and female smokers. Use P, for the proportion of men who smoke. Round...

Question 12 of 19 (1 point) View problem in a pop-up 10.2 Section Exercise 13 Question...

Question 12 of 19 (1 point) View problem in a pop-up 10.2 Section Exercise 13 Question Traiic accidents: Traffic engineers compared rates of traffic accidents at intersections with raised medians with rates at intersections with two-way left-turn lanes. They found that out of 4655 accidents at intersections with raised medians, 2281 were rear-end accidents, and out of 4585 accidents at two-way left-turn lanes, 2037 were rear-end accidents. Check Answ Solve It Guided Solutio Part 1 out of 2 Assuming these...
Question 9 of 11 (1 point) View problem in a pop-up 6.2 Section Exercise 24 (table...

Question 9 of 11 (1 point) View problem in a pop-up 6.2 Section Exercise 24 (table SAT scores: The mean mathematics SAT score was 498, and the standard deviation was 112. A samo of 63 scores is chosen. Use Table A.2 if needed. Part 5 out of 5 Do you think it would be unusual for an individual to get a score greater than 510? Explain. Assume the variable is normally distributed. It (select) be unusual for an individual to...
part 2 Question 1 of 5 (1 point) View problem in a pop-up Find each of...

part 2 Question 1 of 5 (1 point) View problem in a pop-up Find each of the following. Enter your answers rounded to two decimals. Part 1 2a12 for the 95% confidence interval 7/ 21.96 Part 2 out of 5 Z a/2 for the 88% confidence interval CHECK

Question 3 of 6 (1 point) View problem in a pop-up 3.3 Section Exercise A student...

Question 3 of 6 (1 point) View problem in a pop-up 3.3 Section Exercise A student graduated from a 4-year college with an outstanding loan of $10,208, where the average debt is $8588 with a standard deviation of $1808. Another student graduated from a university with an outstanding loan of $12,072, where the average of the outstanding loans was $10,365 with a standard deviation of $2124. Part 1 out of 2 Find the corresponding z score for each student. Round...

Question 7 of 9 (1 point) View problem in a pop-up 7.1 Section Exercise 11 For...

Homework Answers