Question

Question 12 of 31 (1 point) View problem in a pop-up 9.4 Section Exercise 16 National statistics show that 23% of men smoke and 18.5% of women do. A random sample of 159 men indicated that 40 were smokers, and of 129 women surveyed, 17 indicated that they smoked. Part 1 out of 2 Construct a 90% confidence interval for the true difference in proportions of male and female smokers. Use P, for the proportion of men who smoke. Round your answers to three decimal places. А. <P1-P2 L

Answer 1

Question 12) Given that,

For men : n1 = 159 and x1 = 40

For women : n2 = 129 and x2 = 17

Using TI-83 plus calculator we get, the 90% confidence interval for the true difference in proportions of male and female smokers is,

0.045 < p1 - p2 < 0.195

Hi Texas INSTRUMENTS TI-83 Plus 2-PropZInt (.04493, .19465) 15.251572327 2=. 1317829457 n1=159 n2=129 STAT PLOT F1 TBLSET F2 FORMAT F3 CALC F4 TABLE F5 Y- WINDOW ZOOM TRACE GRAPH QUIT INS 2nd MODE DEL LINK LIST A-LOCK ALPHA X,1,0, STAT TEST ANGLE B DRAW c DISTR MATH APPS PRGM VARS CLEAR MATRIX D SIN-1 cos-1 TAN-1 G TT H X-1 SIN COS TAN EE J{ M x2 C ) 10% N 0 V P w 0 R LOG 7 8 9 x S L4 TL5 U L6 V W LN 4 5 6 RCL L1 Y L2 Z L3 ө МЕМ 11 STO 1 2 3 + OFF CATALOGU i ANS ? ENTRY SOLVE ON 0 -) ENTER