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The equilibrium constant for the following reaction is 0.190 at 346K. COBr2(8) PCO(g) + Brz(8) If...
The equilibrium constant for the following reaction is 1.80x102 at 698K 2HI(8)H2( ) +I2(g) If an equilibrium mixture of the three gases at 698K contains 2.35x102 M HI(g) and 2.63x10-2 M H, what is the equilibrium concentration of I? Submit Answer Retry Entire Group 9 more group attempts remaining
6) Distrubuting Equilibrium a) The equilibrium constant, K, for the following reaction is 10.5 at 350 K 2CH2Cl2(g)CH4(g + CCl4(g) An equilibrium mixture of the three gases in a 1.00 L flask at 350 K contains 5.32x10-2 M CH2C2, 0.172 M CH4 and 0.172 M CCI4. What will be the concentrations of the three gases once equilibrium has been reestablished, if 9.58x102 mol of CH4(g is added to the flask? CH2Cl2l [CH4 [CCI4] b) The equilibrium constant, K, for the...
please solve The equilibrium constant, K, for the following reaction is 4.85x10-2 at 641 K. COC12(8) CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 6.59 L container at 641 K contains 0.205 M COCI, 9.98x102 M CO and 9.98*10-M CI2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 15.5 L? [COCI2] = [CO] [Cl] Submit Answer
The equilibrium constant, Kp, for the following reaction is 1.80x10-2 at 698K. 2HI(g) =H2(g) +12(g) If an equilibrium mixture of the three gases in a 14.3 L container at 698K contains HI at a pressure of 1.09 atm and H, at a pressure of 0.929 atm, the equilibrium partial pressure of I, is atm. Submit Answer Retry Entire Group 9 more group attempts remaining
The equilibrium constant, K, for the following reaction is 2.52x10-2 at 620 K. COC12(g) * CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 10.5 L container at 620 K contains 0.264 M COCl2, 8.15x10-2 M CO and 8.15x10-2 M Cl. What will be the concentrations of the three gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 4.32 L? M [COCl2] = [CO] = [Cl2] =...
(1). The equilibrium constant, Kp, for the following reaction is 1.80×10-2 at 698K. 2HI(g) =H2(g) + I2(g) If an equilibrium mixture of the three gases in a 15.5 L container at 698K contains HI at a pressure of 0.399 atm and H2 at a pressure of 0.562 atm, the equilibrium partial pressure of I2 is atm. (2). Consider the following reaction: PCl5(g) =PCl3(g) + Cl2(g) If 1.17×10-3 moles of PCl5, 0.217 moles of PCl3, and 0.351 moles of Cl2 are at...
The equilibrium constant, Kc, for the following reaction is 55.6 at 698 K: H2(g) + I2(g) ---------->2HI(g) 1) Calculate the equilibrium concentrations of reactants and product when 0.309 moles of H2 and 0.309 moles of I2 are introduced into a 1.00 L vessel at 698 K. [H2] = M? [I2] = M? [HI] = M? 2.The equilibrium constant, K, for the following reaction is 1.20×10-2 at 500 K: PCl5(g)------->PCl3(g) + Cl2(g) An equilibrium mixture of the three gases in a...
1) The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) + I2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.311 M HI, 4.18×10-2 M H2 and 4.18×10-2 M I2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 2.85×10-2 mol of I2(g) is added to the flask? 2) The equilibrium constant, K, for the following reaction is 1.20×10-2 at...
5-18 The equilibrium constant, K., for the decomposition of COBr2 COBr2(g) CO(g) + Br2(g) is 0.190. What is K, for the following reaction? 2CO(g) + 2Br2(g) + 2C0Br2(g) A) 0.0361 B) 2.63 C) 5.62 D) 10.5 E) 27.7
Consider the equilibrium between COBr2, CO and Br2 COBr2(g) at 382 K CO(g) + Brz(9) K= 2.08 The reaction is allowed to reach equilibrium in a 13.8-L flask. At equilibrium, [COBr2] = 4.43x10-2 M, [CO] = 0.304 M and [Br2] = 0.304 M. (a) The equilibrium mixture is transferred to a 6.90-L flask. In which direction will the reaction proceed to reach equilibrium? (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 6.90-L...