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RIGHT CLICK ON THE IMAGE AND SELECT "OPEN IMAGE IN A NEW TAB" FOR A LARGER CLEARER IMAGE.A simple random sample of size n=24 is drawn from a population that is normally distributed. The sample mean is found to be x

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Answer #1

We have given that,              
              
Sample mean =53      
Sample standard deviation =12  
Sample size =24      
Level of significance=1-0.90=0.1      
Degree of freedom =23      
              
t critical value is (by using t table)=1.714      
.\bar{x}\pm t*\frac{S}{\sqrt{n}}= 53 \pm 1.714 *(\frac { 12 } {\sqrt{ 24 }})=( 48.8016 , 57.1984 )

Lower confidence limit=   48.80
      
Upper confidence limit=   57.20

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