Question

Q3(33.33%) Calculate the absolute maximum moment due to mo shown. Loading moving BOK BOK HOK 120k 36 PE

Answer 1

Question 60k ook yok 20k to to 8 8 -* g b A B 3oft sold let a= Ift be aff c= 3 ft finding the location of resultant force. R= 60+80 to +20 - 2ook laking moment about 60k 20 x 6 t uox 5 + 80x3 = 200x x x = 2.8 ft from bok. Slep I Assuming maximum hos Bending LOCUB under 8 oki should be by definition at same dis lance from the centre line of beaus as that of resullaint force moment 9+

Gok Isok R yok, 20k t x 2ftify 3ft 0.0.1 AVA & VB + X 15ft 15ft reactions finding VA X 30 = 20 x 15-3.1) + 40 (15-2.1) +80115-11 +60 (15+1+3) VA = 101. ob k. 200- 101.06 VB = 98.933 moment under 80k load absolute maxima (01.068 (15+1) moment - 60x (3.2) - 1334.006 Kup - ft. There is maximum moment may possibility that absolute under Gok load ocur 60 14 yo 20 16 fr PVA & VB

classmate Date Page finding reallions VAX 30 = 60x115+1.4) + 80x (15-1.6) + yo (15-1.6-2) +20 (15-1.6-2-) VA X30 = 2720 VA = go. 666 moment under Gok. = VA X 1 15 15-1.4) 1233. obb-ft So absolute maximum Moment is 1334.006