Question

Problem 4: Shown below is a crank with 5 kN load. Calculate the vertical deflection at the point of the load. The material properties are E = 2003 MPa, G= 80e3 MPa. Show which segment is going through bending and which bending + torsion. (Hint: Total external strain energy = 72 PS) Z 5 kN Y Uim M² dx 400 mm С X ZEI 500 mm UiT aco ST dx 10 mm x 40 mm Section B. 40 mm dia.

Answer 1

Solution :- Data given given : P=5 kn 5 un E = 200 x103 mpa G=80x10²mpa c 0.4m 0140 form B 0.5m > member 'Bc' will subjected to Bending only s lept SUN lomm [] I tomm Ext & kom straim enercy of member Be UBCF 2 EI $15=3* a S852°)d → VBC o 2x2x105x 10X403 12

д UB C = О•53333333 * m3 2х2х205x70x403 б• 533333333x jo5 2-3 2х2х105 х (ох 403 N - Мm_ 12. Y-отт 12. 2 ) ww - 1 1 1 : 85 88V = 240

→ while portion AB will be subjected to bending as well as forsion. T= 5x0.4-24N-M SUN txt UAB = Uimt Uit 05 0.5 2 - dx - UAB da ett S62]€ (7) Port qur J 2 KN m 3 m 7 UAB Elezny +999999160-F tw-mm2 XXgO1X08x6 quaw-ngoo x + x al xong xó 32x 800 mm? 64 2x 1015 mm3 + =) UAB = quewe amsil Xt9999991 to of 2 x 80 x10°x45 x 40fw-mma juu-N 626 x t ex col Kombat =) UAB = 70959.22. N-mm G = U = UAB T UBC 70459.22 + 48828.125 > U = toho N ste-t86655 -mm 3) 4* PS = 119287.345N- >> Š x 5evoNXS = 119287.345 -) Sa houbitott