Question

Q1:(33.33%) Draw the shear and moment elragrams, hable the maximum values of shear and moment, Locate points of inflection, and sketch the deflected shape. 12 kips 15 kips kift 170 K.HU + ht test 1 & lt Q2 (33.33%) Find ye, TAC, TBC for the cable shown. 40 ft cable Length. I A 14C 10pt 15 ft 158

Answer 1

20 Reactions 12K Isk lo koft 170k. It EMRE 20) Rix24 - 10-12x16-15x8+170 50 R2 K JSK 170k. I lokat t (Ri= 6.333K (1) <fy to R, the 12-15=0 R2 = 27-6.333 R₂ = 20.667 K. (A) 8 8 6.333K 8 FBD 20.667k SED V, = 6.333K V₂ = 6.333-12 = -5.667k V3=-5.66745=-20.667 K (Vomen ISED M2 BMD BMD (Area of SED) M, = -10 Kft 12k 15k 10 kift 1700- My =-10+V,48 -10 +6.33388 M2=40.667 K ft VR M3 = 40.667+ V2x8=40.667-5. 66788 R2 Approximated deflected shape M3 = 4.667 Kift

My = --4667 +1348 = -4,667-20-667x8 *-170 koff (Mmon) zero bendery moment locations (point of inflechon) for left most regron 1 Mil IM₂L 10 x 40.667 8-2, x, 8-2, (XF 1.579 st from herge support for middle span 40.667 = 1 M₂) X2 IM31 8-2₂ 4.667 8-22 122= 7.176) ft from 12 kpoint load