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The heights of fully grown trees of a specific species are normally distributed, with a mean of 53.5 feet and a standard devi
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As the underlying distribution is normal here, the distritbuion of sampling mean would also be normal here. The mean and standard deviaiton of the sampling distribution here is given as:

\mu_{\bar X} = \mu = 53.5

\sigma_{\bar X} = \frac{\sigma}{\sqrt{n}} = \frac{5}{\sqrt{13}} = 1.39

The distribution here is therefore given as:

therefore B is the correct graph here.

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