Question

6.2.37 Assume that the reading on the thermometers are normally distributed with a mean of and standard deviation of 100'C Athermometer is sandomly selected and tested Dwa sketch and find the temperature reading corresponding to the percentile. This is the temperature reading seping the bottom from the top 10% Gick the Gick to view Which represents Par? Orose the corect below OD The temperature to Primately Hound to two decimal places as needed

Answer 1

Solution :

Using standard normal table,

P(Z < z) = 84%

P(Z < 0.99) = 0.84

z = 0.99

Using z-score formula,

x = z * $\sigma$ + $\mu$

x = 0.99 * 1 + 0 = 0.99

The temperature for P₈₄ is approximately 0.99^o

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