Question

please help with b-d!

*10-19-1 A radioactive sample's half-life is 30.2 years 1 year - 365 days, 1 day - 24 hours, 1 hour 60 minutes, 1 minute - 60 seconds (a) Find its decay constant in year 1. Keep 4 decimal places. 0.6229 Correct (100,0%) Submit Find its decay constant in sl. Write the result in terms of 10 10,9 Keep 4 decimal places. 7.2764 Correct (100.0 Submit Case 1: The Initial sample is 3.30 kg. (b) What is the mass (in kgof the radioactive material that remains in the sample after 8.0y? Keep 3 decimal places. 0.014 kg Incorrect (0.04) (Correct answer. 2.747) Submit What is the mass in kp of the radioactive material that has decayed in 8.0 yr (from the initial samplej? Keep 3 decimal places. Enter a number Submit attempts remaining) Case 2: The initial sample contains 7.40x10^10 radioactive nuclei. (c) What is the number of the radioactive nuclei that remain in the sample after oyr since the initial time write the result in terms of 1010. Keep 3 decimal places Enter a number Submit (5 attempts remaining What is the initial activity in decays/s (or keep 2 decimal places. decays (R 15 attempts remaining What is the activity in decays (B) after y since the initial time? Keep 2 decimal places Erter a number Submit decaya Subt

Answer 1

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Sola b) ty2 = = 30.2 d = ena = ln2 ti/ 30.2 -years 0.0229 yet > At = Ao e it Ao = 3.3 Kg t = 8 years 7 w d=lna 30-2 in2x8 Soy = 3.3 e 30.2 At = 2.746 kg / So, the material material remaining is 2.746 Kg Therefore , decayed material = 3.3 – 2.746 =0-554 kg No = 74 X 100, t = 8 years, Nt Nť = (7.4x100) - het zX8 Nt = 6+159 x 100 / t = 8 years, talna 30-2 No e dit d) 10 A = A NE Nt → undecayed nucki Initially , NE = No = - No = 74 X 100 A = No = lna x 7.4x10 30-2 X 365X24 X 60 X 60 A = 53.86 decayals (B9) After 8 years, Ny = 6.159 X 100 A = AN = ln2 x 6.159 X 100 So, 30.2X365 X24X60X60 At = 44.82 decays/s (Bq}