Question

Prelab 1) A charge q is accelerated through a voltage difference V. Write an equation showing conservation of energy for this

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Imu?+ 9V- 1 / 2 mu? energy conservation equation u: initial speed I= final speed mass of charge m: → 2 magnetic field B = Bo

Add a comment
Know the answer?
Add Answer to:
Prelab 1) A charge q is accelerated through a voltage difference V. Write an equation showing...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 2) A+ particle is moving toward the top of the page. A uniform magnetic field is...

    2) A+ particle is moving toward the top of the page. A uniform magnetic field is pointing out of the page. a. What is the direction of the magnetic force on the particle at the instant described? b. What is the angle between the charge's velocity and the magnetic force upon it? c. As the particle moves, the magnetic force stays perpendicular to its velocity. What does this say about shape of its subsequent path?

  • 2.032 4. An electron is accelerated through potential difference of 150 V from rest and then...

    2.032 4. An electron is accelerated through potential difference of 150 V from rest and then enters a region of uniform magnetic field traveling perpendicular to the field. The magnitude of magnetic field is 0.50 T. a) What is the magnitude of magnetic force acting on the electron (5.8x10-14 N), and b) what is the radius of the path? (8.3x10 m) Note: The mass of electron is 9.11 x 103 kg, and the charge of electron is 1.6x 10-1 C...

  • Part A ) A charge is accelerated across a voltage difference. Part B) After being sped...

    Part A ) A charge is accelerated across a voltage difference. Part B) After being sped up, it ends up in a region with a uniform B- field. Part C) The magnetic force is perpendicular to the charge’s velocity; it acts as a centripetal force. The charge travels in a circular path. To calculate the charge to mass ratio of electron and to compare it with its accepted value of 1.759 x 1011CKg Theory: Charges will be sped up and...

  • Electrons (mass m, charge –e) are accelerated from rest through a potential difference V and are...

    Electrons (mass m, charge –e) are accelerated from rest through a potential difference V and are then deflected by a magnetic field B that is perpendicular to their velocity. The radius of the resulting electron trajectory is:

  • An electron in a vacuum is first accelerated by a voltage of 31200 V and then...

    An electron in a vacuum is first accelerated by a voltage of 31200 V and then enters a region in which there is a uniform magnetic field of 0.253 T at right angles to the direction of the electron’s motion. The mass of the electron is 9.11 × 10−31 kg and its charge is 1.60218 × 10−19 C. What is the magnitude of the force on the electron due to the magnetic field? Answer in units of N.

  • 2. A proton with charge gp 1.6 x 10 19C and mass M, is accelerated through...

    2. A proton with charge gp 1.6 x 10 19C and mass M, is accelerated through a potential difference V. The proton then enters a region of con stant magnetic field B oriented perpendicular to its path. In this region, the proton's path is circular with radius Rp Another particle with the same charge as the proton but a different mass M, follows under the same conditions. Its radius R., is 1.4 times as large as Rp. what is the...

  • Help me solve this question asap a) Write the expression for the force acting on an...

    Help me solve this question asap a) Write the expression for the force acting on an electron carrying a charge e moving with velocity v when it enters perpendicularly into (i) an electric field of intensity E b) Sketch two separate diagrams of the direction of field, velocity and path of ) With reference to your diagrams, state two differences between the electric (ii) a magnetic field of intensity B the electron and the force acting on it for the...

  • An alpha-particle has a charge of +2e and a mass of 6.64 * 10^-27 kg. It...

    An alpha-particle has a charge of +2e and a mass of 6.64 * 10^-27 kg. It is accelerated from rest through a potential difference that has a value of 1.10 * 10^6 V and then enters a uniform magnetic field whose magnitude is 2.80 T. The alpha-particle moves perpendicular to the magnetic field at all times. What is the speed of the alpha-particle What is the magnitude of the magnetic force on it What is the radius of its circular...

  • A. An α-particle has a charge of +2e and a mass of 6.64 × 10-27 kg....

    A. An α-particle has a charge of +2e and a mass of 6.64 × 10-27 kg. It is accelerated from rest through a potential difference that has a value of 1.67 × 106 V and then enters a uniform magnetic field whose magnitude is 2.49 T. The α-particle moves perpendicular to the magnetic field at all times. What is (a) the speed of the α-particle, (b) the magnitude of the magnetic force on it, and (c) the radius of its...

  • An α-particle has a charge of +2e and a mass of 6.64 × 10-27 kg. It...

    An α-particle has a charge of +2e and a mass of 6.64 × 10-27 kg. It is accelerated from rest through a potential difference that has a value of 1.09 × 106 V and then enters a uniform magnetic field whose magnitude is 2.63 T. The α-particle moves perpendicular to the magnetic field at all times. What is (a) the speed of the α-particle, (b) the magnitude of the magnetic force on it, and (c) the radius of its circular...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT