Question

2. Consider a logical address space of 4 pages of 1024 words each, mapped onto a physical memory of 16 frames. a. How many bits are there in the logical address? b. How many bits are there in the physical address?

Answer 1

given there are 4 pages each of 1024 words

so total there are 4*1024 = 2¹² words

in which we need 12 bits to represent this 2¹² words

b)

there are 16 frames = 2⁴ frames

so we need 4 bits in the physical address