5. What was the focal distance (f) when the radius of curvature was 0.8 and index...

Question

Question

$5. What was the focal distance (f) when the radius of curvature was 0.8 and index of refraction was 1.6? 6. Calculate the rad$

Answer 1

Answer #1

=(1-1) (n-1) f f = R 2(n-1) R2 R1 and R2 are radii of curvature of two sides of lens. these are equal. by sign convention R1

Distanec towards left from the optic centre of lense should be considered as negetive.(sign convention)

Pls keep the question limit.

(Hint for 9th : use the same equation used in 7th and 8th question)

Answer 2

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