a.) Determine the image distance for an object d0 = 6.500 cm from a diverging lens of radius of curvature 5.200 cm and index of refraction 1.750. (Express your answer as a positive quantity.)
b.)What is the magnification of the object? (Be sure to insert the proper sign if needed.)
c.)what is the nature of the image
Homework Answers
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a.) Determine the image distance for an object d0 = 6.500 cm
from a diverging lens...
Determine the image distance di for an object do=5.100 cm from a diverging lens with radius...
Determine the image distance di for an object do=5.100 cm from a
diverging lens with radius of curvature R=4.080 cm and index of
refraction 1.700. Express your answer as a positive quantity.
|di|=
cm
What is the magnification m of the object? Be sure to insert the
proper sign if needed.
m=
object --- -------- d。 一
A candle name 9.10 cm from a lens produces a real image 13.30 cm from the...
A candle name 9.10 cm from a lens produces a real image 13.30 cm from the lens. The lens has one flat side and one curved side, is made of glass with an index of refraction of 1.52, and is surrounded by air, (a) Calculate the focal length of the lens. Be sure to include the appropriate sign and units. (b) Calculate the radius of curvature of the curved side of the lens. (c) Is the curved side convex or...
1.) An object is placed in front of a diverging lens with a focal length of...
1.) An object is placed in front of a diverging lens with a focal length of 17.7 cm. For each object distance, find the image distance and the magnification. Describe each image. (a) 35.4 cm location _____cm magnification _____ nature real virtual upright inverted (b) 17.7 cm location _____ cm magnification _____ nature real virtual upright inverted (c) 8.85 cm location _____ cm magnification _____ nature real virtual upright inverted 2.) An object is placed in front of a converging lens...
A lens produces a real image of a real object. a) Is the image inverted or upright? b) Is the lens diverging or conver...
A lens produces a real image of a real object. a) Is the image inverted or upright? b) Is the lens diverging or converging? c) Is the image enlarged or reduced in size? d) If two convex lenses identical in size and shape aremanufactured from glass with two different indices of refraction,would the focal length of the lens with the greater index ofrefraction (lens 1) be larger or smaller than that of the otherlens (lens 2)?
An object placed 20 cm in front of a lens results in an image being formed...
An object placed 20 cm in front of a lens results in an image being formed 24 cm behind the lens. Each surface of the lens is convex (bulging away from the optical plane) with the same radius of curvature, and the index of refraction of the glass composing the lens is Tiens =1.4. What is the radius of curvature of either side of this lens (to the nearest tenth of a cm)? Note, once again, the focal length of...
A negative or diverging thin lens has a focal length of 10 cm. a) An object...
A negative or diverging thin lens has a focal length of 10 cm. a) An object is placed 30 cm from the lens. Find the image distance and explain if the image is real or virtual. b) Explain if the image is upright or upside down and if it is smaller or larger than the object.
A diverging lens has a focal length of magnitude 21.2 cm. (a) Locate the images for each of the following object distan...
A diverging lens has a focal length of magnitude 21.2 cm. (a) Locate the images for each of the following object distances. 42.4 cm distance cm location in front of A 21.2 cm distance location cm in front of 10.6 cm distance location in front of cm 4 (b) Is the image for the object at distance 42.4 real or virtual? o real o virtual Is the image for the object at distance 21.2 real or virtual? o real o...
A 20 cm tall object is located 70 cm away from a diverging lens that has...
A 20 cm tall object is located 70 cm away from a diverging lens
that has a focal length of 20 cm. Use a scaled ray tracing to
answer parts a-d.
a. Is the image real or virtual?
b. Is the image upright or inverted?
c. How far from the lens is the image?
d. What is the height of the image?
e. Now use the thin lens equation to calculate the image
distance and the magnification equation to determine...
A converging lens with a focal length f1 = 9.00 cm is located 18.0 cm to...
A converging lens with a focal length f1 = 9.00 cm is located 18.0 cm to the left of a converging lens with index of refraction of 1.52 and a radius R = 6.24 cm. An object stands 14.0 cm to the left of the first lens in the combination. Draw the Ray diagrams! (a) Locate the final image relative to the lens on the right. (b) Obtain the overall magnification. (c) Is the final image real or virtual? With...
A diverging lens has a focal length of magnitude 22.6 cm. (a) Locate the images for...
A diverging lens has a focal length of magnitude 22.6 cm. (a) Locate the images for each of the following object distances. 45.2 cm distance cm location (behind or in front of lens) 22.6 cm distance cm location (behind or in front of lens) 11.3 cm distance cm location (behind or in front of lens) (b) Is the image for the object at distance 45.2 real or virtual? Is the image for the object at distance 22.6 real or virtual?...
A candle name 9.10 cm from a lens produces a real image 13.30 cm from the lens. The lens has one flat side and one curved side, is made of glass with an index of refraction of 1.52, and is surrounded by air, (a) Calculate the focal length of the lens. Be sure to include the appropriate sign and units. (b) Calculate the radius of curvature of the curved side of the lens. (c) Is the curved side convex or...
An object placed 20 cm in front of a lens results in an image being formed 24 cm behind the lens. Each surface of the lens is convex (bulging away from the optical plane) with the same radius of curvature, and the index of refraction of the glass composing the lens is Tiens =1.4. What is the radius of curvature of either side of this lens (to the nearest tenth of a cm)? Note, once again, the focal length of...
A negative or diverging thin lens has a focal length of 10 cm. a) An object is placed 30 cm from the lens. Find the image distance and explain if the image is real or virtual. b) Explain if the image is upright or upside down and if it is smaller or larger than the object.
A diverging lens has a focal length of magnitude 21.2 cm. (a) Locate the images for each of the following object distances. 42.4 cm distance cm location in front of A 21.2 cm distance location cm in front of 10.6 cm distance location in front of cm 4 (b) Is the image for the object at distance 42.4 real or virtual? o real o virtual Is the image for the object at distance 21.2 real or virtual? o real o...
A 20 cm tall object is located 70 cm away from a diverging lens
that has a focal length of 20 cm. Use a scaled ray tracing to
answer parts a-d.
a. Is the image real or virtual?
b. Is the image upright or inverted?
c. How far from the lens is the image?
d. What is the height of the image?
e. Now use the thin lens equation to calculate the image
distance and the magnification equation to determine...
A converging lens with a focal length f1 = 9.00 cm is located 18.0 cm to the left of a converging lens with index of refraction of 1.52 and a radius R = 6.24 cm. An object stands 14.0 cm to the left of the first lens in the combination. Draw the Ray diagrams! (a) Locate the final image relative to the lens on the right. (b) Obtain the overall magnification. (c) Is the final image real or virtual? With...
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