Question

Suppose a Lean work center is being operated with a container size of 25 units and a demand rate of 100 units per hour. Also assume it takes 180 minutes lead time to fulfill a downstream container request. Assuming a safety stock factor of 5 percent, how many containers should be required? Select one: O a. none of these O b. 756.0 containers O c. 12.6 containers O d. 1,080.0 containers O e. 18.0 containers

Answer 1

solution :

given data  

n =25

μ = 100 per hour

μ_l = 180 min = 3 hours

r = 5 = 0.05

this is a lean work center so we use the ' Kanban ' formula to solve the problem

* n . k ≥  μ_l . μ_d .( 1+r )................. 1

Here  

no of containers = k

kanban container size = n

average lead time for repienshiment = μ_l

average demand rate = μ_d

safter facror = r

Now put the values in above formule and calculate

K  ≥ 100 * 3 ( 1+ 0.05 ) / 25

K ≥   100 * 3 ( 1.05 ) / 25

K ≥   315 / 25

K ≥   12.6

hence option " c " is correct

  

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