Question

Each of the double pulleys shown has a centroidal mass moment of inertia of 0.25 kg m?, an inner radius of 100 mm, and an outer radius of 150 mm. The mass 14.9 kg and the bearing friction is neglected bo Required into 00 Determine the velocity of the cylinder 3 s after the system is released from rest (Round the final answer to two decimal places) (You must provide an answer before moving to the next part) The velocity of the cylinder 3 Wher the system is released from realis mus!

Answer 1

Given ra olom Stos R = 0.15 m Application of principle of Impulse momestum theeran I - 0.25 kcam 2 Mc = 14.9 kg ve VC ४ Anqatay Velocitey Ofpally A * VC = Oil WA lovc (22 VP- Ryue cond OF velocity ☆ Elo5 VC, V = 0.15 lox VC 1.5 Vc cond WB = & angular velouty of 0. 3 WB 15 Vc and OF Impulse of # To apply the prmciple mimentum for party B are need FBD the seperate Systems,

pully B t=3.See to sec. Тр IWBO B at t=35 extemal impulse. at trosec Here Emb o I (WB), (To xt) ra Tox txol - 01 25 (15 Vc) 37.5 Uch 5 TOE Pully toTo f mel mere

Velocites of the cylinder 3s after the lysters is released forms leat Ema 0 0 fact) r-Cot) R = IWA + (moucbri N Wco 1419 x9.81 t. C 3 sec then Kreu - (14.9 X9181) x3x0.1- (lot) (0.15 ) = 0.25 (love)+Choir +14.9% 4c xol Tot 37-5 from Ą 3.8507 37.5 Vc yo45 = 2.54ct laua uc Vc = 4.5606 mis (ans) Vea 4,561 mis 62 To calculate Tensics too in the cord Tot = 37.5 Vc Tox3=37*5841561 To= 37.5841561 = 57,0125 N 3