Q1 The common-base amplifier shown in figure below has hib = 15 ohm, hrb = 4*10^-5,...

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Question

Answer 1

Answer #1

hi=150 bext= 4x105 bfp=-0.992 hod=44157 h-modet. To w R5=50 +] Eloka VA I BR=9.12VER-२३ Vs Shin 15r hoto hable B B 2 Z; a lok

→ Ax = -0.992 X6.43 7X103 – 925 7 V/v 15 Vo -425.7 V/v At 9n but sid! vi t Rs = 50 Vs } Z=14.9 Abbly voltage divisionsule Vo

Answer 2

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