ANSWER:
Why is it necessary to check that np 25 and 252 5 OA. It is necessary...
1. 2.
Why is it necessary to check that np 25 and nq 25? ^ O A. It is necessary to check that np 25 and nq 25 to be certain that the minimum value of the sample size, n, is met. OB. It is necessary to check that nộ 25 and nĝ 5 because the confidence intervals estimating the population proportions will overlap if these values are less than 5. O C. It is necessary to check that np...
Question Help If np 25 and nq 25. estimate P(at least 5) with n = 13 and 05 by using the normal distribution as an approximation to the binomial distribution, p <5 or ng 5, then state that the normal approximation is not suitable Select the correct choice below and, if necessary in the answer box to complete your choice OA P(at least 5) (Round to three decimal places as needed) OB. The normal distribution cannot be used
If np 25 and nq 25, estimate P(fewer than 6) with n = 13 and p = 0.6 by using the normal distribution as an approximation to the binomial distribution; if np<5 or ng<5, then state that the normal approximation is not suitable. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. P(fewer than 6) = (Round to four decimal places as needed.) OB. The normal approximation is not suitable.
Decide whether the normal sampling distribution can be used. It can be used, test the dam about the population proportion p at the given level of significance a using the given sample statistics Claim p 0.26 0.05, Sample statistics: p=0.22, n = 100 Can the normal sampling distribution be used? O A No, because ng is less than 5. OB. Yes, because both np and ng are greater than or equal to 5. OC. No, because np is less than...
Decide whether the normal sampling distribution can be used. If it can be used, test the claim about the population proportion p at the given level of significance c using the given sample statistics Claim; p<0.14; a =0.05: Sample statistics: p=0.12, n = 25 Can the normal sampling distribution be used? O A. No, because np is less than 5. OB. Yes, because pq is greater than a = 0.05. OC. Yes, because both np and nq are greater than...
If np 2 5 and nq 25, estimate P(fewer than 3) with n 13 and p 0.4 by using the normal distributiorn as an approximation to the binomial distribution; if np <5 or nq<5, then state that the normal approximation is not suitable Select the correct choice below and, if necessary, fill in the answer box to complete your choice O A. P(fewer than 3)- (Round to four decimal places as needed.) B. The normal approximation is not suitable Click...
Decide whether the normal sampling distribution can be used. If it can be used, test the claim about the population proportion p at the given level of significance a using the given sample statistics. Claim; p<0.09; a = 0.05; Sample statistics : P = 0.08, n = 25 Can the normal sampling distribution be used? O A. No, because ng is less than 5. O B. Yes, because pq is greater than a = 0.05. O C. No, because np...
According to a survey in a country, 35% of adults do not own a credit card. Suppose a simple random sample of 200 adults is obtained Complete parts (a) through (d) below. (a) Describe the sampling distribution of the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of below. O A. Approximately normal because ns 0.05N and np(1-P)< 10 OB. Not normal because ns0.05N and...
In a study of government financial aid for college students, it becomes necessary to estimate the percentage of full-time college students who earn a bachelor's degree in four years or less. Find the sample size needed to estimate that percentage. Use a 0.02 margin of error and use a confidence level of 99%. Complete parts (a) through (c) below. a. Assume that nothing is known about the percentage to be estimated. n (Round up to the nearest integer.) b. Assume...
The numbers of successes and the sample sizes for independent simple random samples from two populations are provided for a two-tailed test and a 95% confidence interval. Complete parts (a) through (d). Xy = 21, n = 60, X2 = 22, n2 = 100, a = 0.05 Click here to view a table of areas under the standard normal curve for negative values of Click here to view a table of areas under the standard normal curve for RoSive values...