Question

The pathway of a ball thrown in the air is modelled by the equation 5y = - 4x2 + 40x, where y represents the ball's height in metres after x seconds. The ball will reach its highest point at the vertex. a) Solve the equation - 4x² + 40x = 0 and hence find when the ball strikes the ground. (b) Find the vertex of your equation. c) Graph your function. (d) Find the maximum height that the ball will reach.

Answer 1

a -4040 sy -4x² +40x so .کی - 4x² tho (x)=0 thx²= 4400 22² 2ox x= 10 seconds. ball stity the ground (5,100) . (10,0) the renten of the equation is (5,100) which can be seen by the graph Hotted lo dy o کر رہے meninm Jon at nos 100. -) g

І. (5,100)-verten (1) 1 (10,0) (strikes the land (0,0) d. emenina of the fa in de is da In 20. y' (2) -8 at 8 5 - 8x+8=0 425 . so cut uas y(s), 100. (monimum height).