Question

Solve the triangle shown to the right. Round the lengths of sides to the nearest tenth and angles to the nearest degree. 950 b-4 a-6 A B с CR (Do not round until the final answer. Then round to the nearest tenth as needed.) A- (Round to the nearest degree as needed.) (Round to the nearest degree as needed.)

Answer 1

с to Jow e cosires :- According b=4 a = 6 c? a? +62 - 2ab cosc А to с c² = 1612 + (412-2(6) (4) cosas' 36 + 16 - 48 cos gso ac? 52-48 cosas 0 52-48 cosas 52 -) 7.5 J Now, According to law of sines :- a C Sina Sinc -) 6 7.5 Sina sings » SinA = 6 sin 95° 7.5 А 6 singgo sin I' 7.5

0 - A ² 53 [After rounding to nearest degre] As we know, Sum of all ongles of a trienn gle is 180° [interior angle] . A + B + c = 180 o -) 53° + B + gs' . 180 -) 53° 180° - 95° را - B - 32° Hence, C ~ 7.5 0 A 53 B ✓ 32