Question

i need help with two parts of the same problem the degree changes

Racecar Ais traveling on a straight portion of the track while racecar is waveling on a criar portion of the track. The speed of racecar Ais 270 km/h and the speed of racecar is 230 km/h. At the instant shown the speed of Ais increasing at the rate of 10 m, and the speed of is decreasing theme of 6 Consider the position shown 50 300 m Hered into 1. Determine the velocity of Brelative to A (Round the final answer to one decimal place km 7553

Answer 1

* VA= 270 km/h 4 A sy so 230 km Taking components of ro locity of 'B' l- VB x = V2 sin 40° • VA = 270km/h 906 230 km/h = VB VR cos 40° - VBy VBX Vå sin 40° = 147.84 km/h By VB cos 40° 176.19 km/h in X Relative Velocity of Bw.o.t. A direction (Vorel)x= Vox - VA (147.84) - (-270) 122.16 km/h (towards Right) Relative velocity of 'B' wort A in y direction (Voedly = vby - 176.19 km/h (down ward) - O 122.16 km/h be Vrel 176.19 km/h Vra Vreid + (Vred); = $176.19² + 122.162 = 12 14.4 km/h = ta 176.19 122.16 55.264°

* Note: - In circular motion two components of acceleration a tangential du (at any particular instant) (at any particular instant) exists a radial مها In given en question R = Radius - 3oom VB = 230 km/h = 63.89 m/s decreasing rate of speed of 'B' = (a tangentian) [-6 m/s2 (-ve sign for decreasing speed) ñ 63.59 Ako la radial) = 113.6 m/s2 300 Increasing rate of speed of A : aA = 10 m/s2 ay(+ve) 44А X(tve) 2 58 50° Aradial), (A tang) B 24.275 (ared) & [catogentina) Los 50° + (a radies) sin so] -an - [-(-6) cos s0' + 13.6 sin sor] - (-10) 6 cos so° +13.6 sinso" +10 (towards Right) (Arelly = (a tangentian), sin 50° + Gradiale cos soº -(-6) sin so + (-13-6) cos so 6 sin soo - 13.6 cosso a -4.15 m/s2 m/s2 down ward)

(ar) = 24. 275 m/s2 N (Arelly = 4.15 mis? Arel (chrei) + (ared) = √24.275²+ 4.152 24.63 m/s² if o – tant . 19.7° 4.15 24.275