Kinetic energy is defined as the work done in moving a particle under a force so
So,
ques 1 K.E at x = l
Ques 2 K.E = 3L
ques 3
m= 2kg
L = 3 m
So
here F0 = 1
A particle is moving along the x-axis. It starts from rest at x = 0 and...
1. [6 Points] A particle is moving along the x-axis. It starts from rest at x = 0 and moves to x = L under the action of a variable force with an x-component given by F(x): x2 if 0 SXSL F(x) = 3 L2 Lx if LSX <3L 1 Everything is in SI units: x in meters and F in Newtons. Part 1: What is the particle's kinetic energy at x = L? Express your answer in terms of...
А PARTICLE IS MoviNG ALONG THE X-AXIS IT STARTS. FROM REST AT X - AND MOVES TO X = L UNDER THE ACTION OF A VARIABLG FORCE X-COMPONENT GIVEN Br Fx (x) : WITH An 2 X if FB) 312 IL if Lex 63L EVERY THING IN 57 UNITS : X W METERS AND FW NEWTON A) WHAT IS THE PARTICIE'S KINETIC ENERG EXPRESS YOUR ANSWER IN TERMS OF L AND FO. K (x x=L? = =) = ? IS...
Small typo: In part 1 you are asked to calculate the kinetic energy at x = L, so it should say K(x= L) NOT K(x=L/2). In part 2 you are asked to calculate the kinetic energy at x = 3L, so it should say K(x= 3L) NOT K(x=L). А PARTICLE IS MoviNG ALONG THE X-AXIS IT STARTS. FROM REST AT X - AND MOVES TO X = L UNDER THE ACTION OF A VARIABLG FORCE X-COMPONENT GIVEN Br Fx (x)...
A particle of mass m = 2.70 kg moving along the x axis from x = 0 to x = 10.6 m experiences a net conservative force in an isolated system given by F = 5x − 4, where F is in newtons and x is in meters. (a) What is the work done on the particle by the force F? J (b) What is the change in the potential energy of the system during this motion? J (c) If...
A particle moving along the x axis is acted upon by a single force F = F0e–kx, where F0 and k are constants. The particle is released from rest at x = 0. It will attain a maximum kinetic energy of:
A force F = cx – 3.00x2 ) i acts on a particle as the particle moves along an x axis, with Ē in newtons, x in meters, and c a constant. At x = 0 m, the particle's kinetic energy is 21.0 ; at x = 4.00 m, it is 12.0 J. Find c. Number Units the tolerance is +/-3% Click if you would like to Show Work for this question: Open Show Work
A particle moving along the x axis in simple harmonic motion starts from its equilibrium position, the origin, at t = 0 and moves to the right. The amplitude of its motion is2.50 cm, and the frequency is 1.30 Hz. (a) Find an expression for the position of the particle as a function of time. (Use the following as necessary: t, and ?.) x = (b) Determine the maximum speed of the particle. cm/s (c) Determine the earliest time (t...
A particle with mass 4.0 kg is initially at rest at the origin (x=0). It then moves along the x-axis acted on by a force F(x)=18.0-2.0x2, where F is in Newtons if x is expressed in meters. Find the kinetic energy of the particle when it reaches x=3 m. A Honda Civic (mass=1090 kg) is initially traveling due East at 18.3 m/s when it suddenly collides head on with a Toyota Camry (mass=1612 kg) initially traveling due West at 31.8...
For problems #4 and #5, suppose that a particle is moving along the x-axis and that its position at time=1 is given by the function (). Furthermore, suppose that f(2)=-3 and that f(2)=6. No justification required. 4. At time=2, which one of the following statements is true. Write the letter of the correct answer on the answer sheet. No justification required. a) The particle is to the left of x = 0 and the particle is moving to the left....
The force on a particle is directed along an x axis and given by F = F(underscore)0(x/x(underscore)0 - 1) where x is in meters and F is in Newtons. If F(underscore)0 = 0.63 N and x(underscore)0 = 5.0 m, find the work done by the force in moving the particle from x = 0 to x = 2x(underscore)0 m.