For the following circuit, answer questions 15 through 17. Show all work. R2 1k0 RI SKO...
Score 2. (22 points) For the circuit in Figure 2, the transistor parameters are: 2 0, VN=2V, Ka-1mA/V2, all the capacitors are assumed to act as short circuits at the signal frequency (1) Calculate the Q-point (Vos. I Vos); (2) Sketch the small-signal equivalent circuit, you must label the polarities of the voltages and the direction of the current; (3) Determine the voltage gain A, vo/v (4) Determine the input resistance Ri and output resistance Ro V1 5 10 V...
Please show neat, detailed work, including all small signal analysis if necessary, diagrams and complete algebra steps. Thanks !!! Answer all parts clearly !!! NOTICE THERE MUST BE 4 VOLTAGE GAINS MULTIPLIED TO GET THE FINAL GAIN. THE ANSWER IS We were unable to transcribe this image2) VDD Ideal R3 R7 C5 C3 Vout RI R5 Q4 Rsig C1 Vbia Q1 02 R11 Q3 R2 R4 C2 R6 R8 R10 Rout-? Rin-? Assume all the capacitors are reasonably large at...
Please show neat, detailed work, including all small signal analysis if necessary, diagrams and complete algebra steps. Thanks !!! Answer all parts clearly !!! NOTICE THERE MUST BE 4 VOLTAGE GAINS MULTIPLIED TO GET THE FINAL GAIN. THE ANSWER IS !!! THIS QUESTION DOES NOT NEED ANY MORE INFORMATION !!! We were unable to transcribe this image2) VDD Ideal R3 R7 C5 C3 Vout RI R5 Q4 Rsig C1 Vbia Q1 02 R11 Q3 R2 R4 C2 R6 R8 R10...
3-F) b. Vout = 0.99 Vin 3-E) For the following circuit, with Ri 18 k2, R2 15 k(2, R6 = 40 kQ, V,-10 V, and V,-7 V, find: 22 k2, R 30 k2, R4 20 kQ, Rs- a) the current through Ri, R3, & R6 b) the voltage across R2, R4, & Rs Rs V, 3-F) For the following circuit, what is Vout in terms of Vin for each case? a) R1-100 ?, R2-1 k(2, and R3 = 1.0 M(2...
Calculate the voltage gain (Av) for the loaded Common Emitter Amplifier below: BAC 200 for all transistors. Assume re 15 Q for the CE Amplifier. Ignore re' for the DP Amplifier Vcc 12 V, R1 56 K, R2 10 KQ, R4 22 KQ R3 5.6 KQ, RL 8 RE(CE) 628 0, RE(CC) 330 Rc 3.5 KQ, Enter your results. No units. SR3 R1 RC C3 Vcc C1 Beta Q2a HH Vin Beta Q1 Beta Q2b C4 R4 Vs R2 C2...
Given the circuit below: R3 C1 Vout C2 R1 R3 Vin R2 ts 1 a) derive the transfer function between the input and the output in terms of R1,C1,R2,C2 b) For this and all other parts below, assume Izl<Ipl, i..e that D(s) is a lead-type compensator. The transfer function is written in the following format ts 1 Express quantities K, z, p using R1,C1,R2,C2 Also, express Κα, α, τ using K,z, p c) Observe the values of s-jw on the...
Please answer parts E, F and G given answers for previous steps: a) High Pass Filter or HPF b) Reactance Xc = 1/(2 x pi x f x C) = 1/(2 x 3.14 x 1000 x 47 x 10-9) = 3386.28 Ohm c) Impedance = (15002 + 3386.282) = 3703.63 Ohm d) Cut off frequency = 1/ (2 x pi x R x C) = 1/(2 x 3.14 x 1500 x 47 x 10-9) = 2258 Hz = 2.258 kHz...
1-Clear handwriting 2-Correct answer 3-Organized 4-answer all the questions Please Problem 2 On the circuit on Figure P2, transi stor Q1 has a threshold voltage of Vt = 2 V and a transconductance parameter of k = 100 mA/V2. Note that Vcc = -Vee = 4.5 V. Moreover, capacitors C1, C2, and C3 can be assumed to be very large VDD 4.5.0 R3 25kQ R1 300kn C2 Vout C1 Rsig Q1 1k0 R2 200kn Vsig (R4 2kQ C3 -4.5V VSS...
Amplificabon R3 Av Vin C1- R2 R1 Follow the instructions: 11. Connect the last circuit on the simulation program. 12. Set Vin-3 V (rms) 13. R1-15 KO, R2-30 ΚΩ 14. R3s 20 КО, С. 10 nf 15, Op.Amp (741) Measure and calculate all the needed in the table: f(Hz) 150-1100 1200 I 600 I 800 1K | 2K Vo (V) Av Av (dB) 7. Plot a skitch of curve between F and Av(dB). (Frequency Response) -10 20 10 Hz 20...
please I need details l and....Debate Club | Offic A) Theoretical Design Design a common emitter BJT amplifier with the following requirements: -Rin-10 K2, and Ro-45 ㏀ (Neglect the Early voltage Effect) Vo/Vsig- Gv-40 VIV or 32 dB " VCC-9 V V, IC-1mA, VCE-3.25V and β-100 RL-40 kQ, Rsige I ka, R 1-3R2, and C1-C2-1 μF Voc RC C2 R1 Rsig C1 RL R2 RE B) Verify your design using Orcad Capture Pspice by doing 1) AC sweep (frequency response):...