Part b
We have
Margin of error = Z* sqrt(p̂*(1 – p̂)/n)
We are given
Number of items of interest = x = 236
Sample size = n = 320
Sample proportion = p̂ = x/n = 236/320 = 0.7375
Confidence level = 95%
Critical Z value = 1.96
(by using z-table)
Margin of error = Z* sqrt(p̂*(1 – p̂)/n)
Margin of error = 1.96* sqrt(0.7375*(1 - 0.7375)/320)
Margin of error = 0.048209
Margin of error = 0.048
The margin of error is 0.048.
answer B A department of education reported that in 2007, 66% of students enrolled in college...
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