Question

Use the t-distribution to find a confidence interval for a difference in means μ 1 - μ 2 given the relevant sample results. Give the best estimate for μ 1 - μ 2 , the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed.

A 90% confidence interval for μ 1 - μ 2 using the sample results x ¯ 1 = 10.0 , s 1 = 2.2 , n 1 = 50 and x ¯ 2 = 13.1 , s 2 = 5.3 , n 2 = 50

Enter the exact answer for the best estimate and round your answers for the margin of error and the confidence interval to two decimal places.

Answer 1

Solanon: Ti 10.0 T :13.1 S.2.2 52:53 niso 12.50 got. Confidence internal for M1-M2 d 2010 2 3 hisit M252 nutn2-2 50+so .2 h = 16.810 IS Ho989 N1402-2 ť ta : to 1%, 50+50-2 =toos, gg : 1.6605 Best estimate (81-82) (10.0-13-U = -34

Margint Coror: 50 +886 E: ť XS X ht's = 1.66€5xl.cgega? E = 1.3612 Confidence interval CI= [(81-76) sx this time 1.6605 X 4.0989 ] X est = [(00-13.1) - 1-3-1 1312) C'I:[-H. Hence the confidence interrol 4.4612 -1.7388 Thank you. please like it