Question

Problem 7 Consider the circuit shown in (Figure 1). Suppose that 9,= 130 cos 10,000+ V, where t is in seconds Part A Determine the load impedance for the circuit that will result in maximum average power being transferred to the load. Express your answer in ohms to three significant figures. Enter your answer in rectangular form. View Available Hint(s) VO AXO vec ? 2 = Submit Part B Figure 1 of 1 Determine the maximum average power delivered to the load from Part A. Express your answer to three significant figures and include the appropriate units. View Available Hint(s) 4 mH THA o ? 2014 $400 Z PE Value Units Submit

Answer 1

10,000 naells Solution UMH 2.SHF A tretie Z von Vg บ V 130 COJ 10,000 t ( vg transfer to load for maximum power (0) Z ? is delivered power Maximum for a N/W Ac load to Z when * Ith ZL ų terminal th is thevenin impedance across → La umH a v 7m 104x40103 XL von с u 2.5M Xc you I a T rz we 104x2.5x106

Redraw circuit for Zeh Inoclt- De activate all Sources Source voltage short cireuil juon - juon ണ. You € Zen 7th - -juo + ju0|140) 13- -juot = juox 40 a Yo + JUO - juo t jyo Tt jy л - juo + ( 20 + dois (do. Jalol o th a for Maximeem power Zuz (Ztn) * Il ? (20-jao ) * e ZL. Ansi za (20+ jao) e Iz 52024 202 tanil ( 2 ) 28.2847 (45° & Ansi

b 130 COS C100€) كه v 130 Lou o Polar foon vg juos -juon mm Z = (20 + 120) you Iz 130/0v calculate Maximan Aug power of load, we have to calcuate IL . 2 watt pa Apply kul în > loop- I 13020 f j401, + vol 1,-12) 20 13010 - 0 (40+ juo) 24 40 I2 kuL in loop. I I Apply j40 12 + (80+ ) I2 + 400 I2 - !,) = 0 (60 - jQo) 12 jao) 12 - vol, so 1, (1-5 - 30.5) 12 6o-jao 12 40

put Ii (1-5 - jo's) i, in eq.o 1300 40 I2 13.10 (40+ j40)(1-5-30-5) 12 – 4012 (80 + juo) I2 (40 4052 L 45° I2 + juo) 122 Bolo 13040 2 12010 yof2 Lus A Iza 2-29812-45" A be in will IL sinusoidal from 12 2,2981 CoJ (1044-459) A in Lood P will be - for Max. Aug power W pa (12) me. Re 224) 2 pa 2.2981,2 x 20 S2 watt Ane P ? 52.813 is always Maximum power power of real Aug. load but not apparent power of Load,