Homework Answers
Solution:
Analysis : A simple reverted compund gear train is shown in the figure. The law that governs the velocity ratios in the gears of a reverted compound gear train is given as:
Now this when connected to speed ratios we have:
Therefore
N1/N4 = (T2xT4)/(T1xT3)
1750/N4 = (70x54)/(20x18)
N4 = Nd = 166.667 rpm (CW)
Result: The output shaft rotates at a RPM of 166.67 Clockwise.
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