Question

A perfect emitter with a surface area of 1(104) m2 has a temperature of 10,000K. Calculate...

A perfect emitter with a surface area of 1(104) m2 has a temperature of 10,000K. Calculate its radiant energy in watts. Stefan-Boltzmann's constant is 5.67(10-8) J/(s-m2-K4

0 0
Add a comment Improve this question Transcribed image text
Answer #1

T=10,000 K soll! given A = 10t un for perfect emmitter e=1 from steph Stefan-Boltzmanns law power p = eAGT4 Radiant Energy.

Add a comment
Know the answer?
Add Answer to:
A perfect emitter with a surface area of 1(104) m2 has a temperature of 10,000K. Calculate...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • An animal's body has a skin temperature of 33 °C and is the room temperature where...

    An animal's body has a skin temperature of 33 °C and is the room temperature where the walls are at temperature 29 °C. If the emissivity is 1 and the body area is 1.5 m2. What is the rate of heat transfer by radiation? ( Stefan-Boltzmann constant = 5.67 x 10 -8 J/s m?k4) 42 W 38 W 72 W O 54 W O 63 W

  • How much power (power is the energy per second) is radiated by the person

    Radiation of Energy The rate of heat transfer by emitted radiation is determined by the Stefan-Boltzmann law of radiation: = aeAT4 where o 5.67x10-8 J/s - m2 K is the Stefan-Boltzmann constant, A is the surface area of the object, and T is its absolute temperature in kelvin. The symbol e stands for the emissivity of the object, which is a measure of how well it radiates An ideal jet-black (or black body) radiator has e 1,whereas a perfect reflector has...

  • The rate of heat transfer by emitted radiation is determined by the Stefan-Boltzmann law of radiation...

    The rate of heat transfer by emitted radiation is determined by the Stefan-Boltzmann law of radiation = ceAT4 t where a 5.67x108 J/(s m2. K4) is the Stefan-Boltzmann constant, A is the surface area of the object, and T is its absolute temperature in kelvin. The symbol e stands for the emissivity of the object, which is a measure of how well it radiates. An ideal jet-black (or black body) radiator has e 1, whereas a perfect reflector has e...

  • The energy radiated per unit surface area (across all wavelengths) for a black body with temperature...

    The energy radiated per unit surface area (across all wavelengths) for a black body with temperature 2200. Use 5.67 x 10-8 for the Stefan-Boltzmann constant. The Stefan-Boltzmann Law describes the power radiated from a black body in terms of its temperature. Specifically, the total energy radiated per unit surface area of a black body across all wavelengths per unit time is proportional to the fourth power of the black body's thermodynamic temperature

  • SHOW YOUR WORK Find the rate of emission of radiant energy by unit of Area Hr,...

    SHOW YOUR WORK Find the rate of emission of radiant energy by unit of Area Hr, if the emissivity of the surface, e, is 0.90 and the temperature is 600K. Stefan-Boltzmann constant is 5.67 x 10-8 W/m2K4

  • The hot glowing surfaces of stars emit energy in the form ofelectromagnetic radiation. It is...

    The hot glowing surfaces of stars emit energy in the form of electromagnetic radiation. It is a good approximation to assume that the emissivity e is equal to 1 for these surfaces.Part AFind the radius RRigel of the star Rigel, the bright blue star in the constellation Orion that radiates energy at a rate of 2.7×10^31 W and has a surface temperature of 11,000 K. Assume that the star is spherical.Use σ=5.67×10^−8 W/m2⋅K4 for the Stefan-Boltzmann constant and express your...

  • 5 and 7 Question 5 3 ptgu HC Calculate the blackbody surface temperature of Mars (3...

    5 and 7 Question 5 3 ptgu HC Calculate the blackbody surface temperature of Mars (3 sig figs, answer in °C). Solar Flux on Mars (Fs) = 590 W m2 Stefan-Boltzmann constant (0) = 5.67 x 108W m2 K4 Earth's radius = 6.4 x 10 m Assume Mars' albedo = Earth's Albedo (It is worth thinking about whether this is a good assumption, or not! Question 6 O pts Upload a picture of your work from question 5. This is...

  • Absorb Incident radiant onorgy Reflected Emitted Absorbed Retained Black Black Incident radiant energy Reflected Emitte Retained...

    Absorb Incident radiant onorgy Reflected Emitted Absorbed Retained Black Black Incident radiant energy Reflected Emitte Retained Absorbed Silver coated Silver coated A person with a surface area of 1.20 m2, and a skin temperature of 27 °C, is in a room that is at a temperature of 17.6 °C. The emissivity of the skin is 0.895, The Stefan-Boltzmann constant is 5.67 x 10-8 W/(m2K). (a) How much energy is radiated by the person in 1 minute? Keep 2 decimal places....

  • 4. Temperature

    Assuming a filament in a 100W light bulb acts like a perfect blackbody, what is the temperature of the hottest portion of the filament if it has a surface area of6.3*10^-5m^2? The Stefan Boltzmann constant is 5.67*10^-8W/(m^2*K^2).

  • Find the radius RRigel of the star Rigel, the bright blue star in the constellation Orion...

    Find the radius RRigel of the star Rigel, the bright blue star in the constellation Orion that radiates energy at a rate of 2.7×1031W and has a surface temperature of 11,000 K. Assume that the star is spherical. Use σ=5.67×10−8W/m2⋅K4 for the Stefan-Boltzmann constant and express your answer numerically in meters to two significant figures.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT